Lets see how that works: Before bringing in the numbers, lets mention that another way of showing the acid-dissociation reaction (which is more accurate) is to include the water and formation of the hydronium ion (H 3 O + ): The equilibrium constant for this reaction would be: Since the concentration of the water is constant and very large compared to the acid, it is included in the formula of K a : Therefore, the [H 2 O] term does not appear in the K a formula, and we have: Just like in any equilibrium reaction, the stronger the acid, the larger the K a
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